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It says:
int B1::* mpB1 = &D::i; // Unambiguous
int D::* mpD = &D::i; // Ambiguous conversion
Which is wrong.
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jwakely commentedon Jan 9, 2017
Yes, both are ambiguous. @jensmaurer or @zygoloid what is this meant to say?
jensmaurer commentedon Jan 9, 2017
As discussed on the core reflector starting at http://lists.isocpp.org/core/2017/01/1441.php, the example is correct: There is only one B1::i member, and that is unambiguously found by the algorithm described in this section.
See also CWG 39 / N1626.