remove the condition to clarify the case that the parameter pack is n… #4707
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I still think "if the pack was introduced by a pack expansion" should be removed for bullet 8.1. For example,
template<int...N> struct B{ B(){fun(N...);}};
, Isn't that each element instantiated inN...
does designate the corresponding template argument? However,int... N
is just a template parameter pack declaration instead of a pack expansion(where the template parameter packN
is introduced by the parameter pack declaration). If add the condition seems that the latter clause is not suitable for this case. For type template parameter pack, it is the same.template<template<class T>... TMPL> struct C{using T = U<TMPL....>;};
,template<class...T> struct D{using T = tuple<T...>;}
, in all of these cases, the pack is introduced by the parameter pack declaration that is not a pack expansion itself, but each element actually does designate the ith template argument.