[stmt.return] p5 says:

The copy-initialization of the result of the call is sequenced before the destruction of temporaries at the end of the full-expression established by the operand of the return statement, which, in turn, is sequenced before the destruction of local variables ([stmt.jump]) of the block enclosing the return statement.

What does the which in the sentence refer to? It can be read as

1. "which" refers to "The copy-initialization of the result of the call"
2. "which" refers to "the destruction of temporaries"

According to this example:

#include <iostream>
struct Drop{
    Drop(int id):id_(id){

    }
    int id_;
    ~Drop(){
        std::cout<<"drop "<< id_<<std::endl;
    }
};
int g(){
    Drop x{0};
    {
        Drop y{1};
        return ((Drop&&)Drop{2},0);
    }
    return 1;
}
int main(){ 
   auto c = g();
   std::cout<<"main\n";
}

The outputs are consistent in major implementations, which is

drop 2
drop 1
drop 0
main

It seems that which wants to refer to "the destruction of temporaries"

Suggested Resolution

The copy-initialization of the result of the call is sequenced before the destruction of temporaries at the end of the full-expression established by the operand of the return statement, and the destruction of the temporaries is sequenced before the destruction of local variables ([stmt.jump]) of the block enclosing the return statement.